Hello from MrBillDoesMath!
Answer:
8 and 10
Discussion:
Let x and x+2 be as described in the Question. Then
(x+2)^2 - x^2 = 36 => (x+2)^2 = x^2 + 2x + 4
x^2 + 4x + 4 - x^2 =36 => the x^2 terms cancel
4x + 4 = 36 => subtract 4 from both sides
4x = 36 -4 - 32 => divide both sides by 4
x = 32/4 = 8
So the integers are 8 and 10 (8+2)
Check: 10^2 - 8^2 = 100 -64 - 36.
Thank you,
MrB