Final answer:
To produce a dip angle of 62° in the center of the tank, a current of 18.8 A should be passed through the coil.
Step-by-step explanation:
In order to produce a net magnetic field in the center of the tank with a dip angle of 62°, you will need to pass a current through the coil that creates a magnetic field that adds to the Earth's magnetic field. The change in magnetic field strength needed can be calculated using the tangent function:
Tan θ = B_coil / B_earth
Solving for B_coil and substituting the given dip angles, we have:
B_coil = Tan(dip angle) * B_earth = Tan(62°) * 50 μT = 1.19 mT
Using the formula for the magnetic field inside a current-carrying loop:
B_coil = (μ0 * I * N) / R
Where μ0 is the permeability of free space, I is the current through the coil, N is the number of turns in the coil, and R is the radius of the coil. Simplifying for I, we have:
I = (B_coil * R) / (μ0 * N) = (1.19 mT * 0.5 m) / (4π × 10^-7 T·m/A * 200) = 18.8 A
Therefore, you should pass a current of 18.8 A through the coil to produce a net magnetic field in the center of the tank with a dip angle of 62°.