Question

(-4y^4 +5y^2+30y+49)÷(2y–5)

Answer 1

`-2y^(3) -5y^(2)-10y-10 -(1)/(2y-5)`

Explanation:

To perform the division we need to write the polynomial in descending order with all missing coefficients (if any), thus, the original polynomial is written as the following:

`-4y^(4)+0y^(3)+5y^(2)+30y+49`

The attached picture reveals the whole procedure to obtain the following:

`-2y^(3) -5y^(2)-10y-10 -(1)/(2y-5)`

Remember, the term remaining after the last subtract step is the remainder and must be written as a fraction in the answer.