Question

Select the two values of x that are Roots of this equation 2x-3=-5x^2

Answer 1

-1

Explanation:

Answer 2

The roots are -1 and 0.60

Explanation:

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`2x-3=-5x^(2)`

so

`5x^(2)+2x-3=0`

`a=5\\b=2\\c=-3`

substitute in the formula

`x=\frac{-2(+/-)\sqrt{2^(2)-4(5)(-3)}} {2(5)}`

`x=\frac{-2(+/-)√(64)} {10}`

`x=\frac{-2(+/-)8} {10}`

`x=\frac{-2(+)8} {10}=0.60`

`x=\frac{-2(-)8} {10}=-1`

therefore

The roots are -1 and 0.60