Question

What is the period and what is the amplitude of this function?

y = 3sin(x/4)+2

Answer 1

Period = 8π

Amplitude = 3

Explanation:

We have given a function.

y = 3sin(x/4)+2

We have to find the period and amplitude of the given function.

Comparing the given function and y = asin(bx)+c , we have

a = 3 and b = 1/4 = 0.25 and c = 2.

Period of function is:

Period = 2π / b

Period = 2π / .25

Period = 8π

The amplitude of function is absolute value of a.

Amplitude = 3

The amplitude of function is 3 and period is 8π.

Answer 2

period

8π

Amplitude

3

Explanation:

The periodicity of a*sin(bx±c)±d is;

sine base periodicity/absolute (b) =
`(2pi)/((1)/(4) )=8pi`

The Amplitude of a*sin(bx±c)±d is; absolute (a). In this case, the Amplitude is the absolute value of 3 which is 3.