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4 votes
Factor by grouping
2m^3+6m^2+3m+9​

User Yashesh
by
4.6k points

1 Answer

4 votes

Answer:

Explanation:

Final result :

(2m2 + 3) • (m + 3)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "m2" was replaced by "m^2". 1 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((2 • (m3)) + (2•3m2)) + 3m) + 9

Step 2 :

Equation at the end of step 2 :

((2m3 + (2•3m2)) + 3m) + 9

Step 3 :

Checking for a perfect cube :

3.1 2m3+6m2+3m+9 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2m3+6m2+3m+9

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 3m+9

Group 2: 6m2+2m3

Pull out from each group separately :

Group 1: (m+3) • (3)

Group 2: (m+3) • (2m2)

-------------------

Add up the two groups :

(m+3) • (2m2+3)

Which is the desired factorization

Polynomial Roots Calculator :

3.3 Find roots (zeroes) of : F(m) = 2m2+3

Polynomial Roots Calculator is a set of methods aimed at finding values of m for which F(m)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers m which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 2 and the Trailing Constant is 3.

The factor(s) are:

of the Leading Coefficient : 1,2

of the Trailing Constant : 1 ,3

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 5.00

-1 2 -0.50 3.50

-3 1 -3.00 21.00

-3 2 -1.50 7.50

1 1 1.00 5.00

1 2 0.50 3.50

3 1 3.00 21.00

3 2 1.50 7.50

Polynomial Roots Calculator found no rational roots

Final result :

(2m2 + 3) • (m + 3)

Processing ends successfully

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User DaveEP
by
5.0k points