Question

It takes Mike 1 hour to get to work each day. He first rides the train, which travels at an average rate of 65 miles per hour. Then he rides the subway train, which travels at an average rate of 25 miles per hour. If the total distance that he travels from home to work is 61 miles, how many minutes does Mike spend riding the subway each morning?

Answer 1

6 minutes.

your welcome :)

Explanation:

Answer 2

The time taken by Mike riding subway train is 6 min .

Explanation:

Given as :

Total time taken by Mike from home to work = t = 1 hours

Total distance between home and work = 61 miles

The average speed of train = 65 mph

Let The distance cover while travelling on train = d miles

The average speed of subway train = 25 mph

Let The distance cover while travelling on subway train = (61 - d) miles

Let the time taken by Mike riding subway train = x min

Now, From formula

∵ Time =
`(\textrm distance)/(\textrm speed)`

So, Total time taken = time taken on train + time taken on subway train

Or, t =
`(d)/(65)` +
`(61 - d)/(25)`

Or, 1 =
`(5 * d + 13 * (61 - d))/(325)`

Or, 1 × 325 = 5 d - 13 d + 793

Or, 325 = - 8 d + 793

Or, 8 d = 468

∴ d =
`(468)/(8)`

i.e d = 58.5

So, The distance cover while travelling on subway train = (61 - d) = 61 - 58.5 miles

I.e The distance cover while travelling on subway train = 2.5 miles

Now, Time taken by Mike on subway train = x =
`(\textrm distance)/(\textrm speed)`

Or, x =
`(2.5)/(25)` hour

Or, x = 0.1 hour

∵ 1 hour = 60 minutes

∴ 0.1 hour = 60 × 0.1 = 6 minutes

So, The time taken by Mike riding subway train = x = 6 min

Hence,The time taken by Mike riding subway train is 6 min . Answer