Question

A shark is swimming at 10 m/s west when it spots some floating bait caught in some seaweed straight ahead. After 10 s, and traveling at a velocity of 15 m/s, the shark reaches the bait. What was the shark's average acceleration? A. 0.5 m/s² B. 0.5 m/s² east C. 0.5 m/s² west D. 10 m/s²

Answer 1

The average acceleation is 0.5 m/s² west

Step-by-step explanation:

As we know that

Acceleration =
`(Final velocity - Initial velocity)/(time)`

Putting the values

Acceleration =
`(20-10)/(10)`

Acceleration = 0.5

Since the shark was moving in west so the Acceleration will be in west too

Answer 2

C. 0.5 m/s² west

Step-by-step explanation:

The shark's average acceleration is given by:

`a=(v-u)/(t)`

where

v = 15 m/s west is the final velocity

u = 10 m/s west is the initial velocity

t = 10 s is the time taken

Substituting data into the equation, we find:

`a=(15 m/s-10 m/s)/(10s)=0.5 m/s^2`

and since the acceleration is positive, it means that it is in the same direction as the velocity, so west.