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3 votes
Two factory plants are making TV panels. Yesterday, Plant A produced

9000

panels. Six percent of the panels from Plant A and
1
%

of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was
4
%

?

User Mahani
by
7.5k points

1 Answer

2 votes

Answer:

Explanation:

Alright, lets get started.

Plant A produced 9000 panels.

Suppose plant B produced x panels.

Number of defective panels plant A produced =
9000*(6)/(100)=540

Number of defective panels plant B produced =
x*(1)/(100)=(x)/(100)

Total defective panels =
540 + (x)/(100)

We are given that, overall percentage of defective panels from the two plants was 4%.


(9000+x)(4)/(100)=540 + (x)/(100)


360+(4x)/(100)=540+(x)/(100)


(3x)/(100)=180

Cross multiplying


x=(180*100)/(3)


x=6000

hence plant B produced 6000 panels. : Answer

Hope it will help :)

User Cervyvin
by
6.5k points