Question

Enrique has $50 in his lunch account and spends $5 per day from the account. Maya has $46 in her lunch account and spends $4 per day from the account. Which equations model the situation? 50 – 5x = y and 46 – 4x = y 5x + 50 = y and 4x + 46 = y 5x – 50 = y and 4x – 46 = y 5 – 50x = y and 4 – 46x = y

Answer 1

For this case we have:

Let the variable "x" be the number of days that Enrique and Maya have lunch

Let the variable "y" be the amount of money left in the account

So, we have:

If Enrique has $ 50 and spends $ 5 per day:

`50-5x = y`

If Maya has $ 46 and spends $ 4 per day:

`46-4x = y`

Thus, the equations that model the problem are:

`50-5x = y\\46-4x = y`

Answer:

Option A