Question

Solve the following addition and subtraction problems. a. 90 cg 95 mg + 7g 12 cg 18 mg b. 4 kg 2hg + 14 kg + 5 kg 17 hg c. 12 dag 5 g – 7 g d. 8 kg – 9 hg

Answer 1

a) 900mg + 95mg + 7,000mg + 120mg + 18mg = 8,133mg

b) 4kg + .2kg + 14kg + 5kg + 1.7kg = 24.9kg

c) 120g - 5g - 7g = 108g

d) 8kg - .9kg = 7.1kg

Explanation:

Part a

90 cg 95 mg + 7g 12 cg 18 mg

Convert measurements so that all has same unit.

1 cg = 10mg; 1g = 1000 mg; Therefore:

90cg = 900mg; 7g = 7,000 mg; 12cg = 120mg

Add

900mg + 95mg + 7,000mg + 120mg + 18mg = 8,133mg

Part b.

4 kg 2hg + 14 kg + 5 kg 17 hg

Convert measurements so that all has same unit.

1hg = .1kg; Therefore:

2hg = .2kg; 17hg = 1.7

Add

4kg + .2kg + 14kg + 5kg + 1.7kg = 24.9kg

Part C

12 dag 5 g – 7 g

Convert measurements so that all has same unit.

1 dag = 10g; Therefore:

12dag = 120g

Subtract

120g - 5g - 7g = 108g

Part d.

8 kg – 9 hg

Convert measurements so that all has same unit.

1hg = .1kg; Therefore:

9hg = .9kg

Subtract

8kg - .9kg = 7.1kg

Answer 2

Hello!

The answers are:

a. 8,133mg

b. 24.9kg

c. 108g

d. 7.1 kg

Why?

First, we need to convert all the units for each option, in order to be able to do the addition and substractions, so:

For a.

`1cg=10mg\\1g=1000mg`

So,

`90cg*(10mg)/(1cg)+95mg+7g*(1000mg)/(1g)+12cg*(10mg)/(1cg)+18mg=900mg+95mg+7000mg+120mg+18mg=8133mg`

For b.

`1hg=0.1kg`

So,

`4kg+2hg*(0.1kg)/(1hg)+14kg+5kg+17hg*(0.1kg)/(1hg)=4kg+0.2kg+14kg+5kg+1.7kg=24.9kg`

For c.

`1dag=10g`

Let's assume the missing signs as negative signs

so,

`12dag*(10g)/(1dag)-5g-7g=120g-5g-7g=108g`

For d.

`1hg=0.1kg`

Let's assume the missing signs as negative signs

So,

`8kg-9hg*(0.1kg)/(1hg)=8kg-0.9kg=7.1kg`

Have a nice day!