Question

Some thermodynamic properties of ethanol are listed in the table. Thermodynamic Properties Property Value c (solid) 0.5 J/g °C c (liquid) 1.0 J/g °C c (gas) 2.0 J/g °C Melting Point −114 °C Boiling Point 78 °C How much heat is released when 40.0 g of ethanol cools from −120 °C to −136 °C? 640 J 580 J 320 J 290

Answer 1

It's 320

Step-by-step explanation:

Answer 2

Option C - 320J

Explanation

Since ethanol solid at −120 °C and is only cooling down (it won’t change states) . The amount of Thermodynamic properties values c is given in form of solid, liquid and gas. Amount of energy released is calculated below.

Formula,

= change in temperature x specific heat capacity for solid ethanol x 40

=> 0.5 x 16x 40 = 320J

Therefore, the 320J of heat is released when 40.0g of ethanol cools.