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A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form. A) (x - 3)2 + (y - 8)2 = 9 B) (x + 3)2 + (y + 8)2 = 9 C) (x - 3)2 + (y - 8)2 = 64 D) (x + 3)2 + (y + 8)2 = 64

User JESii
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2 Answers

4 votes

Answer:

Explanation:

A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form.

A) (x - 3)2 + (y - 8)2 = 9<==2x+2y=31

B) (x + 3)2 + (y + 8)2 = 9<==2x+2y=−13

C) (x - 3)2 + (y - 8)2 <==2x+2y=86

D) (x + 3)2 + (y + 8)2 = 64<==2x+2y=42

User Unixmiah
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5.0k points
6 votes

Answer:

the answer is B

Explanation:

User Farha Ansari
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5.3k points
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