196k views
4 votes
The solution set, all real numbers greater than or equal to one, proves which of the following inequality statements to be true? -5x ≥ 6x - 11 -5x ≤ 6x - 11 5x ≤ 6x + 11 -5x ≤ 6x + 11

User Sneaker
by
6.1k points

1 Answer

0 votes

Answer:

-5x ≤ 6x - 11

Explanation:

Solving inequalities involves the same steps as equations with the exception that when multiplying or dividing by a negative coefficient of the variable, the inequality sign will flip. The solution to one of the inequalities given must be x ≥ 1. Given this answer, you can solve each to find the matching inequality:

-5x ≥ 6x - 11 or -11x ≥ -11 or x ≤ 1 (flip the sign due to negative coefficient)

-5x ≤ 6x - 11 or -11x ≤ -11 or x ≥ 1 (flip the sign)

5x ≤ 6x + 11 or -x ≤ 11 or x ≥ -1

-5x ≤ 6x + 11 or -11x ≤ 11 or x ≥ -1

User Florian Fasmeyer
by
5.3k points