196k views
4 votes
The solution set, all real numbers greater than or equal to one, proves which of the following inequality statements to be true? -5x ≥ 6x - 11 -5x ≤ 6x - 11 5x ≤ 6x + 11 -5x ≤ 6x + 11

User Sneaker
by
8.4k points

1 Answer

0 votes

Answer:

-5x ≤ 6x - 11

Explanation:

Solving inequalities involves the same steps as equations with the exception that when multiplying or dividing by a negative coefficient of the variable, the inequality sign will flip. The solution to one of the inequalities given must be x ≥ 1. Given this answer, you can solve each to find the matching inequality:

-5x ≥ 6x - 11 or -11x ≥ -11 or x ≤ 1 (flip the sign due to negative coefficient)

-5x ≤ 6x - 11 or -11x ≤ -11 or x ≥ 1 (flip the sign)

5x ≤ 6x + 11 or -x ≤ 11 or x ≥ -1

-5x ≤ 6x + 11 or -11x ≤ 11 or x ≥ -1

User Florian Fasmeyer
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories