Answer:
$82.45
$4932.45
$4932.45
$9782.45
$166.30
$9948.75
Explanation:
Since we're computing for two different years with two different principals, we need to compute them separately.
First we start with year 1.
Since the n will be 1 for both years, we can use the formula:
![A=P(1+r)^(t)](https://img.qammunity.org/2020/formulas/mathematics/high-school/wh2y58ryi717m78iqyt0bjjm2uj7s6maan.png)
P = 4850
r = 1.7% or 0.017
t = 1
Let's plug in our values to find the Ending balance.
![A=4850(1+0.017)^(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zofyecco4um1optv9ye5qes9jf8dpd5b8d.png)
![A=4850(1.017)^(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9s2ipu0tpjtkw56647t88um4ijylpadm4j.png)
![A=4850(1.017)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j51m9ohptiprolcq98ebdgxg98h2rcr4pw.png)
![A=4932.45](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4gj2fwqp8wnz7y7cfqpsxis0d26l3fnjsl.png)
The new ending balance will be $4932.45.
To find for the amount of interest earned, we simply subtract the ending balance to the new balance.
I = 4932.45 - 4850
I = $82.45
Laura's account earned $82.45 after the first year.
Now for year 2.
Laura's beginning balance will be $4932.45.
Her new balance will be her beginning balance plus the amount deposited.
New balance = $4932.45 + $4850
New balance = $9782.45
Now using her new balance we compute for her ending balance.
P = $9782.45
r = 1.7% or 0.017
t = 1
![A=9782.45(1+0.017)^(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v9iyhprwebo3ai41l1jnqdj64oujxle55a.png)
![A=9782.45(1.017)^(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bgwkyj2pydjjzw8rae5jgin4xkip7y8xue.png)
![A=9782.45(1.017)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qskv9h4ba9f2tb9uu8ulmj7pob5v0lngla.png)
![A=9948.75](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rac88dcbkrvsyqqbp7dwh87yyeigtuyivi.png)
Laura's ending balance after the second year is $9948.75.
Now let's compute for her interest.
I = 9948.75 - 9782.45
I = $166.30
Laura's account earned $166.30 after the second year.