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Find the equation of the line perpendicular to y = -4x + 3 that also interacts the point (8,1)

User Gisell
by
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1 Answer

5 votes

Answer:

The answer is "
y = (1)/(4)(x-4)".

Explanation:

Given:


Line = y= -4x+3 \\ \\point= (8,1)

The formula for the standard Equation of a line:


\to y= mx +c

compare the above line value:


m= -4\\\\c= 3

When a line is perpendicular so, the m value is:
= (1)/(4)


\to m_1 * \m_2 = -1\\\\\to -4 * m_2= -1\\\\\to m_2 = (-1)/(-4)\\\\\to m_2= (1)/(4)

Line equation when one point and m is given:


\to (y-y_1) = m (x- x_1)\\\\\to (y-1) = (1)/(4)(x- 8)\\\\\to 4y-4 = x- 8\\\\\to 4y = x-8+4\\\\\to 4y = x-4\\\\\to y = (1)/(4)(x-4)\\

User Vermaete
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3.1k points