Question

Please help me ASAP?!!

Answer 1

the answer 05 and 4 13

Answer 2

(0,-5) and (-4,3)

Explanation:

The given equations are

`\left \{ {{x^2+y^2=25} \atop {2x+y=-5}} \right.`

Make y the subject in the second equation;

`y=-2x-5`

Substitute into the first equation;

`x^2+(-2x-5)^2=25`

Expand:

`x^2+4x^2+20x+25=25`

`x^2+4x^2+20x+25-25=0`

`5x^2+20x=0`

`5x(x+4)=0`

`\Rightarrow x=0,x=-4`

When x=0,

`y=-2(0)-5=-5`

This gives; (0,-5)

When x=-4

`y=-2(-4)-5=3`

This gives (-4,3)