Question

The function f(x)=x2-12+5 written in vertex form is f(x)=(x-6)2-31 what are the coordinates of the vertex

Answer 1

`\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)=x^2-12x+5~\hfill f(x)=(x-\stackrel{h}{6})^2\stackrel{k}{-31}~\hfill \stackrel{vertex}{(6,-31)}`