Question

The length of a rectangle is 5 more than 2 times its width. The perimeter is 40 inches. What is the width of the rectangle?

Answer 1

The width of rectangle = 5 inches

Step-by-step explanation:

Formula:-

Permeter of rectangle = 2(l + b)

l - Length of rectangle

b - Breadth of rectangle

It is given that,the length of a rectangle is 5 more than 2 times its width. The perimeter is 40 inches

Let 'x' be the width of rectangle.

length of rectangle = 2x + 5

To find the value of x

It is given that perimeter = 40 inches

Perimeter = 2(l + b) = 40

2(2x + 5 + x) = 40

3x + 5 = 20

3x = 20 - 5 = 15

x = 15/3 = 5

To find the length and width

Width = x = 5 inches

Length = 2x +5 = 2*5 + 5 = 15 inches

Answer 2

The width of the rectangle is 5 in

Step-by-step explanation:

Assume that the width of the rectangle is x

We are given that:

The length is 5 more than 2 times the width

This means that:

Length of the rectangle = 2x + 5

Now, we are given that the perimeter of the rectangle is 40 inches

Therefore:

Perimeter = 2 (length + width)

40 = 2 (2x + 5 + x)

20 = 3x + 5

20 - 5 = 3x

3x = 15

x = 5

From the above calculations, we can conclude that:

Width of the rectangle = x = 5 in

Length of the rectangle = 2x + 5 = 2(5) + 5 = 10 + 5 = 15 in

Hope this helps :)