2 Answers

Bernk · Answer 1 · 2020-12-08T18:34:08+0000

For this case we have that, by definition, a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

In addition, its roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

If we have the following equation:

$\frac {1} {4} x ^ 2 + 5 = 0$

So we have to:

$a = \frac {1} {4}$

b = 0, there is no term that accompanies x.

c = 5

Asnwer:

$a = \frac {1} {4}\\b = 0\\c = 5$

Jaybee · Answer 2 · 2020-12-12T05:32:10+0000

Answer:

The answer is a = 1/4 , b = 0 and c = 5

Explanation:

∵ 1/4 x² + 5 = 0 is a quadratic equation

∵ ax² + bx + c = 0 is the general form of the quadratic equation

∴ a = 1/4

∴ b = 0

∴ c = 5

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