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Which function has a range of (-pi/2,pi/2)

Which function has a range of (-pi/2,pi/2)-example-1
User Dejo Dekic
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2 Answers

0 votes

Answer:

B.) y=tan^-1 x

Explanation:

just took the test and got 100%

User Thomas Kammeyer
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3 votes
ANSWER


y = \tan^( - 1) (x)

EXPLANATION

The inverse tangent function has two horizontal asymptotes


y=\pm (\pi)/(2)


Therefore it has a range of


( - (\pi)/(2),(\pi)/(2) )

The second choice is the correct option.
Which function has a range of (-pi/2,pi/2)-example-1
User Mcjudd
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5.6k points