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what is an equation of the line that passes through the point (6, -1) and is parallel to the line 2x-3y=12

User Mibrahimy
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1 Answer

2 votes

Answer:

y = -(2/3)x - 5

Explanation:

First we need to find the slope of the line 2x - 3y = 12 by solving for y...

2x - 3y = 12

-3y = -2x + 12

y = (2/3)x - 4

Parallel lines have the same slope, so the new line has a slope of (2/3), the equation for a line is y = mx + b, so we have m, and a point (x, y) of (6, -1), so plug in all the values and solve for b...

-1 = (2/3)(6) + b

-1 = 4 + b

-5 = b

So the line parallel is y = (2/3)x - 5

User Cthulhu
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