Answer:
Choices D is the correct answer.
Explanation:
We have given an equation.

We have to find solution of given equation.
Let

then,

Putting values in given equation, we have
y²-y+4 = 6
y²-y+4-6 = 0
y²-y-2 = 0
Applying factorization of above equation, we have
y²-2y+y-2 = 0
y(y-2)+1(y-2) = 0
(y-2)(y+1) = 0
Applying Zero-Product Property to above equation, we have
y-2 = 0 or y+1 = 0
y = 2 or y = -1
or

Taking cube on both sides of above equation, we have
x = (2)³ or x = (-1)³
x = 8 or x = -1 which are the answer.