162k views
1 vote
Question 1.

The line plots show the number of minutes two different age groups of teenagers spent online the previous week.

Select from the drop-down menus to complete each statement.

The range is | A. Greater for data set 1 [13 to 15 year olds] B. Greater for data set 2 [ 16 to 18 year olds] or C. Is the same for both data sets. The mean is |A. Greater for data set 1 [13 to 15 year olds] B. Greater for data set 2 [ 16 to 18 year olds] or C. Is the same for both data sets.

Question 2.
The line plots show the results of the number of dollars two different age groups of teenagers earned in one week.



Select from the drop-down menus to complete each statement.

The range is | A. The same for both data sets B. Greater for the 14 to 16 year olds or C. Greater for the 14 to 19 year olds. The median is | A. The same for both data sets B. Greater for the 14 to 16 year olds or C. Greater for the 14 to 19 year olds.

Question 1. The line plots show the number of minutes two different age groups of-example-1
Question 1. The line plots show the number of minutes two different age groups of-example-1
Question 1. The line plots show the number of minutes two different age groups of-example-2

2 Answers

3 votes

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

The range is B. Greater for data set 2

The mean is B. Greater for data set 2

2) The range is C. Greater for the 14 to 19 year olds

The median is C. Greater for the 14 to 19 year olds

Hope This Helps You!

Good Luck (:

Have A Great Day ^-^

ʜᴀɴɴᴀʜ

User Shahar Shokrani
by
5.9k points
2 votes

Answer:

Question: 1)

The range is:

B. Greater for data set 2 [ 16 to 18 year olds]

The mean is:

B. Greater for data set 2 [ 16 to 18 year olds]

Question: 2)

The range is:

C. Greater for the 17 to 19 years old.

The median is:

C. Greater for the 17 to 19 years old.

Explanation:

Question 1)

Minute spent online (13 to 15 years)

21 1

24 1

26 1

27 2

28 3

31 1

34 1

The minimum value=21

and maximum value= 34

Hence, Range=Maximum value-Minimum value

Range=34-21

Range=13

and mean is:


Mean=(21+24+26+27* 2+28* 3+31+34)/(1+1+1+2+3+1+1)\\\\\\Mean=(274)/(10)\\\\\\Mean=27.4

and Minute spent online (16 to 18 years)

12 1

21 1

28 4

30.5 1

34 1

35 1

36 1

The minimum value=12

and maximum value= 36

Hence, Range=Maximum value-Minimum value

Range=36-12

Range=24

and mean is calculated as follows:


Mean=(12+21+28* 4+30.5+34+35+36)/(1+1+4+1+1+1+1)\\\\\\Mean=(280.5)/(10)\\\\\\Mean=28.05

Hence, we see that:

The range is greater for data set 16 to 18 years ( since 24>13)

and the mean is also greater for data set 16 to 18 years ( since 28.05>27.4 )

Question 2)

14 to 16 years:

30 2

40 1

50 4

60 1

70 2

80 2

100 3

150 1

The minimum value=30

and maximum value= 150

Hence, Range=Maximum value-Minimum value

Range=150-30

Range=120

Also,we know that the median always exist in the middle of the data hence, when we arrange the data in the increasing order :

30 30 40 50 50 50 50 60 70 70 80 80 100 100 100 150

The median lie between 60 and 70

Hence, Median=(60+70)/2=65

Median=65

17 to 19 years:

50 1

100 2

120 1

140 1

150 1

160 1

170 1

180 1

200 2

210 1

220 1

The minimum value=50

and maximum value= 220

Hence, Range=Maximum value-Minimum value

Range=220-50

Range=170

Also,we know that the median always exist in the middle of the data hence, when we arrange the data in the increasing order :

50 100 100 120 140 150 160 170 180 200 200 210 220

Hence, the number that comes in the middle is: 160

Hence, Median= 160

The range is same for both the second data( since 170>120) and the median is greater for 17 to 19 years.

User Muffe
by
5.2k points