Question

The temperature of a chemical solution is originally 21^\circ\text{C}21 ? C21, degree, C. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^\circ\text{C}75 ? C75, degree, C after 121212 minutes of heating.

Answer 1

T = 21 + 4.5x

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Answer 2

The rate is
`4.5(\°C)/(min)`

Explanation:

we know that

The formula to calculate the rate or slope between two points is equal to
`m=(y2-y1)/(x2-x1)`

Let

x----> the time in minutes

y-----> the temperature in Celsius degrees

we have

`A(0,21)\ B(12,75)`

Substitute the values

`m=(75-21)/(12-0)`

`m=(54)/(12)=4.5(\°C)/(min)`