The function
![2x^2-44x-150](https://img.qammunity.org/2020/formulas/mathematics/college/hsr6f4gtw7foeohbej0vf55qlrx7sdotr9.png)
is a parabola concave up, whose solutions are
![2x^2-44x-150=0 \iff x^2-22x-75=0](https://img.qammunity.org/2020/formulas/mathematics/college/yg9otbgx6f4i6qfmlbsavi0ph1vvfdit09.png)
from here, you can use the quadratic formula
![x_(1,2) = (-b\pm√(b^2-4ac))/(2a)](https://img.qammunity.org/2020/formulas/mathematics/college/ynoh9slhipibnkv77c5rhctfip82f4a2ql.png)
to find that the solutions of the parabola are
![-3,\ 25](https://img.qammunity.org/2020/formulas/mathematics/college/2mnu9lxz2py6qc8yotsv8yq6n9qnbzf4th.png)
So, the parabola is positive if
(which wouldn't make sense in our case) or
![x<25](https://img.qammunity.org/2020/formulas/mathematics/college/pupf322itwdfz5dfz4ums39p53ernfkpyy.png)
So, if Tanya caters 25 meals she breaks even, and starting with the 26th meal she will begin to profit.