Question

Insert a monomial so that each result is an identity( *− 3b4)(3b4 +*) = 121a10 − 9b8

Answer 1

(11a^5 - 3b^4) (3b^4 + 11a^5) = 121a^10 - 9b^8

Explanation:

I got the 11 part by doing √121 = 11

I got the a^5 by knowing that a needs to have the same exponent both times and 5+5=10. Thats how I got the a^5 part.

Answer: (11a^5 - 3b^4) (3b^4 + 11a^5) = 121a^10 - 9b^8

Answer 2

The answer for this is (-3b4) (3b4 +) = 121a10-9b8