Question

Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side of the equation as a single fraction. y=7x-1/4;(5,5)

The equation is y=
Please help it’s urgent! :)

Answer 1

`y=-(4)/(7) x+(55)/(7)`

Explanation:

Change the given equation to slope-intercept to get
`y=(7)/(4)x-(1)/(4)`. When you multiply the slopes of perpendicular lines, you get -1. -1 divided by
`(7)/(4)` is
`-(4)/(7)`. The slope of the new line is then
`-(4)/(7)`. The perpendicular line passes through (5, 5) so you can have the equation
`5=-(4)/(7) (5)+b`. Simplifying gets
`b = (55)/(7)` . So now the final equation for the perpendicular line is
`y=-(4)/(7) x+(55)/(7)`