Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

The moose population in a New England forest can be modeled by the function y =
60x/1 + 0.625x.

What is the value of the horizontal asymptote? Describe it's meaning in the context of the problem.

Answer 1

D

Step-by-step explanation: i got that ? and i got it right actually not kidding!

Answer 2

Answer: A & B are the same answer --> 96, max

Explanation:

Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:

• If m > n, then there is no H.A.
• If m = n, then y = coefficient of numerator ÷ coefficient of denominator
• If m < n, then y = 0

In the given problem, m = 1 and n = 1 so the H.A. is:

`y=(60)/(0.625)\quad \rightarrow \quad y=96`

This is the maximum number of moose that the forest can sustain at one time.