Given is :
Let the rate of walking in the evening be = x km/h
As Ed wants to walk at a rate if 1 km/h more in the morning, then rate in morning becomes = x+1 km/h
So, distance is 12 km, speed is x+1 km/h
![time=(distance)/(speed)](https://img.qammunity.org/2020/formulas/mathematics/college/2ekvtrhp4uuer66mmbfv545zviu41jrrcb.png)
Total time is = 5 h 24 m or convert it into hours, it becomes
= 5.4 hours
Time in morning becomes =
![(12)/(x+1)](https://img.qammunity.org/2020/formulas/mathematics/college/bdqaw3je0qoy9zuxd1ramwo5wg0tw8511v.png)
Time in evening becomes =
![(12)/(x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/w11m9tp37otukhd4ipazvm14lg0bx3p8fv.png)
So equation becomes=
![(12)/(x+1)+(12)/(x)=5.4](https://img.qammunity.org/2020/formulas/mathematics/college/254ez64mxopqtfv2fzn97mham9y9wa6qwo.png)
Solving this quadratic equation, we get, x= -5/9 or x=4
As X cannot be negative so neglect -5/9.
Solving by using x=4, we get rate as x= 4+1 =5 km/h
Hence, rate in the morning is 5 km/h.