This question is asking to create 5 of your own questions, so here are mine with the process on how I got each:
Question 1: Given c(x) = 8x + 32, find the range of c for the domain {1, 3, 5}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by 8, and adding by 32.
c(1) = 8(1) + 32 = 8 + 32 = 40
c(3) = 8(3) + 32 = 24 + 32 = 56
c(5) = 8(5) + 32 = 40 + 32 = 72
Range: {40, 56, 72}
Question 2: Given d(x) = x - 7, find the range of d for the domain {-2, 3}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, and subtracting 7.
d(-2) = -2 - 7 = -9
d(3) = 3 - 7 = -4
Range: {-9. -4}
Question 3: Given f(x) = 7x + 738, find the range of f for the domain {1.5, 11}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by 7, and adding 738.
f(1.5) = 7(1.5) + 738 = 10.5 + 738 = 748.5
f(11) = 7(11) + 738 = 77 + 738 = 815
Range: {748.5, 815}
Question 4: Given g(x) = -2804x + 7268, find the range of g for the domain {50, 75, 256}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by -2804, and adding 7268.
g(50) = -2804(50) + 7268 = -140200 + 7268 = -132932
g(75) = -2804(75) + 7268 = -210300 + 7268 = -203032
g(256) = -2804(256) + 7268 = -717824 + 7268 = -710556
Range: {-132932, -203032, -710556}
Question 5: Given h(x) = -3x - 4, find the range of h for the domain {1, 2, 3}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by -3, and subtracting by 4.
h(1) = -3(1) - 4 = -3 - 4 = -7
h(2) = -3(2) - 4 = -6 - 4 = -10
h(3) - -3(3) - 4 = -9 - 4 = -13
Range: {-13, -10, -7}