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A gas at constant pressure occupies 0.400 L at 50.0°C. What volume will it have at 300.°C? If you could show work that would really be appreciated.

User Fabio K
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This can be solved using the Combined Gas Law. The formula for that is


(P_(1) V_(1) )/(T_(1) ) = (P_(2) V_(2) )/(T_(2) )

Let's go ahead and fill in our known values. Since pressure remains the same, it doesn't matter what number we use, so let's assume 1 atm on both sides. For temperature, remember to convert it to Kelvin first (K = C + 273).


((1 atm) (0.400 L))/((323 K)) = ((1 atm) (x L))/((573 K))

Go ahead and simplify both sides.

0.001238 =
((x L))/((573 K))

Multiply both sides by 573.

0.7095 = x L

So, at 300° C, your gas will occupy 0.7095 L.

User RonnieDickson
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