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5 square root of (n+4)^3

User Sheena
by
6.6k points

1 Answer

4 votes

Answer:

n = -4

Explanation:

Solve for n over the real numbers:

5 sqrt((n + 4)^3) = 0

Divide both sides by 5:

sqrt((n + 4)^3) = 0

Square both sides:

(n + 4)^3 = 0

Take cube roots of both sides:

n + 4 = 0

Subtract 4 from both sides:

Answer: n = -4

User Leonti
by
5.8k points