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find three consecutive integers such that three times the third is 102 more than the sum of the first and second
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find three consecutive integers such that three times the third is 102 more than the sum of the first and second

User Vromanch
by
5.0k points

2 Answers

6 votes

Answer:

97,98,99

Explanation:

User Jwogrady
by
5.1k points
4 votes

Answer:

97,98,99

Explanation:

x-1 + x + x+1

x-1+x + 102=3(x+1)

2x +101 = 3x+3

2x+98=3x

x=98

User Animuson
by
5.9k points
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