Question

In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports. A student is chosen randomly from this group. What is the probability that the student plays either basketball or football?

Answer 1

18/25 = 72%

Explanation:

P(B ∪ F) = P(B) + P(F) - P(B ∩ F)

= 12/25 + 11/25 - 5/25

= 18/25

The probability a randomly chosen student plays either sport is 18/25 = 72%.