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5 votes
Solve each quadratic equation

3x=0.5x^2 and 0=5x^2-2x+6

User Klinky
by
8.0k points

2 Answers

4 votes

Answer:

X=0,6 for the first

X= 1+or-i/~29/5

Explanation:

User Yongbok
by
8.3k points
3 votes

Answer:

Equation 1. x = 0, 6

Equation 2. No real solution.

Explanation:

Quadratic equations are

3x = 0.5x² and 0 = 5x² - 2x + 6

We have to solve these equations for the value of x.

a). 0.5x² = 3x

Divide the equation by 0.5

x² = 6x

x² - 6x = 0

x(x - 6) = 0

x = 0 or x = 6

b). 5x² - 2x + 6 = 0

We will find the discriminant of the given equation.


(-2^(2)-4* 5* 6)=4 - 120

= -116

Since the discriminant of this equation is negative, solution of the equation will be imaginary.

User Empedocle
by
7.9k points

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