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Write the point slope form of the line that passes through (-8,2) and is perpendicular to a line with a slope of -8

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Answer:


y - 2 = (1)/(8)(x +8)

Explanation:

Perpendicular lines have negative reciprocal slopes. Since the slope of one line is -8, its perpendicular line will have the slope of 1/8.

Substitute m = 1/8 and (-8,2) into the point slope form of a line.


y - y_1 = m(x-x_1)\\y - 2 = (1)/(8)(x --8)\\y - 2 = (1)/(8)(x +8)

User BilluBaziger
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