Question

A total charge of 6.3×10?8 C is distributed uniformly throughout a 2.7-cm radius sphere. The volume charge density is:

Answer 1

`7.6\cdot 10^(-4) C/m^3`

Step-by-step explanation:

The volume charge density is given by:

`\rho = (q)/(V)`

where

q is the charge

V is the volume of the sphere

In this problem, we have:

`q=6.3\cdot 10^(-8) C` is the charge

`r=2.7 cm=0.027 m` is the radius of the sphere, so its volume is

`V=(4)/(3)\pi r^3 = (4)/(3)\pi (0.027 m)^3=8.24\cdot 10^(-5) m^3`

So, the volume charge density is

`\rho = (6.3\cdot 10^(-8) C)/(8.24\cdot 10^(-5) m^3)=7.6\cdot 10^(-4) C/m^3`