Answer:
B). virtual , upright & larger
Step-by-step explanation:
As we know by the mirror formula
![(1)/(d_i) + (1)/(d_o) = (1)/(f)](https://img.qammunity.org/2020/formulas/physics/middle-school/ns8yxf8hzwf5d6xkfcy7ocniz17x3ynwv5.png)
now here we will have
![d_o < f](https://img.qammunity.org/2020/formulas/physics/middle-school/hmyfe67vdywscq8qc5nfc6mfs35p3l88r7.png)
![d_i = ((d_o)(f))/(d_o - f)](https://img.qammunity.org/2020/formulas/physics/middle-school/4v31b13t2jwcfumlu0b1ctbxbtwajqzef2.png)
now for magnification we will have
![M = (d_i)/(d_o)](https://img.qammunity.org/2020/formulas/physics/middle-school/8333rkldw7bvtaijabkvcrxebjkbsz8ssc.png)
now we have
![M = (f)/((d_o - f))](https://img.qammunity.org/2020/formulas/physics/middle-school/majupcu9mtsq2lquz7vu1u4r93preeatk7.png)
here we can say for the magnitude of magnification that it is always greater than 1 for above position of object and also it is negative which shows the image is virtual and upright.
so correct answer will be
B.virtual , upright & larger