Answer:

Step-by-step explanation:
First of all, let's calculate the moment of inertia of the second hand. The moment of inertia of a slender rod rotating about one end is given by

where m is the mass of the rod and L is its length. For the second hand, we have
m = 6.00 g = 0.006 kg
L = 15.0 cm = 0.15 m
So, the moment of inertia is

Then, we have to calculate the angular speed of the second hand, which is given by:

where T is the period of the second hand, which is T=60 s. Substituting,

Now we can finally calculate the angular momentum of the second hand, which is equal to the product of the moment of inertia I and the angular speed
:
