Question

Complex number in standard form

Answer 1

Choice B is the answer.

Explanation:

We have given an expression.

`(3i-(2)/(3))-(6i-5)`

We have to simplify it and write it as complex number in standard form.

a+bi is a complex number in standard form.

`3i-(2)/(3)-6i+5`

Adding like terms, we have

`(-(2)/(3)+5)+(3-6)i`

`((-2+15)/(3))+(-3)i`

`((13)/(3))+(-3)i`

`(13)/(3)-3i` which is standard form of complex number.

Answer 2

B. (13/3 - 3i)

Explanation:

Given: (3i - 2/3) - (6i - 5)

Here we have to subtract.

To simplify we have to combine real numbers and complex number(i.e) terms with "i"

= 3i - 2/3 -6i + 5 [distributed the negative sign inside the parenthesis]

= -2/3 + 5 + 3i - 6i[Combine real numbers and complex numbers]

= 13/3 - 3i

Therefore, the answer is B. (13/3 - 3i)

Hope this will helpful.

Thank you.