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2 votes
Complex number in standard form

Complex number in standard form-example-1
User Crsh
by
7.8k points

2 Answers

7 votes

Answer:

Choice B is the answer.

Explanation:

We have given an expression.


(3i-(2)/(3))-(6i-5)

We have to simplify it and write it as complex number in standard form.

a+bi is a complex number in standard form.


3i-(2)/(3)-6i+5

Adding like terms, we have


(-(2)/(3)+5)+(3-6)i


((-2+15)/(3))+(-3)i


((13)/(3))+(-3)i


(13)/(3)-3i which is standard form of complex number.

User Carlton Gibson
by
7.3k points
3 votes

Answer:

B. (13/3 - 3i)

Explanation:

Given: (3i - 2/3) - (6i - 5)

Here we have to subtract.

To simplify we have to combine real numbers and complex number(i.e) terms with "i"

= 3i - 2/3 -6i + 5 [distributed the negative sign inside the parenthesis]

= -2/3 + 5 + 3i - 6i[Combine real numbers and complex numbers]

= 13/3 - 3i

Therefore, the answer is B. (13/3 - 3i)

Hope this will helpful.

Thank you.

User Stefan Pries
by
8.4k points

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