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One zero of x^3 - 4x = 0 is 0 what are the other zeros of the function

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So you have x^3 - 4x = 0. What you can do is pull out an x from both x^3 and - 4x so it looks like this:


x( {x}^(2) - 4) = 0

Then you can find a number that makes the part inside the parentheses turn into zero. For beginners, it may be easier to write it out seperately and solve for x.


{x}^(2) - 4 = 0

We need to solve for x, so the first step is to add 4 to both sides, so we get something like this:


{x}^(2) = 4

Then, we can square root both sides to get rid of the power on the x, so it looks like this:


x = √(4)

Now, every square root has two answers, a positive and a negative. If we look at the bottom example:


{2}^(2) = 4


{( - 2)}^(2) = 4

We can see that both -2 and 2 to the power of two will equal to 4.

So finally, we get:


x = - 2 \: and \: 2

These are the other 'Zero's for the original function. If you are not sure of what a 'Zero' is, it is where the function crosses over the x-axis on a graph.
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