Question

Solve a triangle with a=32, b=38, and c=46.

Answer 1

Explanation:

we have a triangle with

a=32, b=38, and c=46

We can use the cosine rule to find the angles

It is

`cos A =(b^2+c^2-a^2)/(2bc)`

so plugging all the values we get

`cos A =(38^2+46^2-32^2)/(2.38.46)`

`cos A =(317)/(437)`

A= 43.5

Now for angle B , the formula is

`cos B= (a^2+c^2-b^2)/(2ac)`

plugging all the vaues again we get

`cos B= (32^2+46^2-38^2)/(2.32.46)`

`cos B= (53)/(92)`

B= 54.8

Now since for a triangle A+B+C =180

so C = 180 - 43.5- 54.8

C=81.7

option a