Question

Find the solutions for a triangle with a=16, c=12, b=63, B=63°

Answer 1

B. on edg

Explanation:

Answer 2

The answer is m∠A = 71.6° , m∠C = 45.4° , b = 15.0 ⇒ answer (b)

Explanation:

∵ a = 16 , c = 12 , m∠B = 63°

By using cosine rule:

∵
`b=\sqrt{a^(2)+c^(2)-2ac(cosB)}`

∴
`b=\sqrt{16^(2)+12^(2)-2(16)(12)(cos63)}= 15.022`

By using sin rule:

∵
`(16)/(sinA)=(15)/(sin63)`

∴
`sinA=(16sin63)/(15)=0.9504`

∴ m∠A=71.6°

∴ m∠C = 180 - (71.6 + 63) = 45.4°

∴ A = 71.6° , C = 45.4° , b = 15.0