Answer:
The dimensions of the larger rectangle are
of length by
of width
Explanation:
Let
x-----> the length of the larger rectangle
y-----> the width of the larger rectangle
we know that
------> by similar rectangles
-----> equation A
Find the perimeter of the smaller rectangle
![P=2(6+4)=20\ cm](https://img.qammunity.org/2020/formulas/mathematics/high-school/poixey81ftr3rii511ek8zeb3w6tko4swa.png)
Find the perimeter of the larger rectangle
Subtract the perimeter of the smaller rectangle from 100 cm of string
![P=100-20=80\ cm](https://img.qammunity.org/2020/formulas/mathematics/high-school/qqt0ftplp0vyfmx14s56q159zqvpo4wqw2.png)
Remember that
------>
------> equation B
substitute equation A in equation B
Find the value of x
![x=1.5(16)=24\ cm](https://img.qammunity.org/2020/formulas/mathematics/high-school/j1qym6xc5iporuwmo42p94miqasjfmrfy3.png)
The dimensions of the larger rectangle are
of length by
of width