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if the thermal energy of the system increases by 400 j and 1100 j of heat were added to the system, how much work did the system do

User PsPranav
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2 Answers

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Hi My name is Zach and im not the one at Residential with you so just to let you know the answer is 12 :)

User Visualex
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The equation used here is ΔU=Q-W,

where, ΔU is the change in the system's internal energy, Q is the energy transferred to or from the system by heat, and W is the energy transferred to or from the system by work.

Known:

ΔU=400J

Q=1100 J

W=?

Plug into the equation:

400=1100-W

Therefore W=700 J.

So the system did 700 J of work.

User Tonka
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