4.8k views
1 vote
How many grams of oxygen are required for the combustion of 25.5 grams of magnesium? 2Mg(s) + O²(g) -> 2MgO(s)​

User Kynnemall
by
7.5k points

1 Answer

2 votes

Step 1 : Convert grams of magnesium to moles using n = m/MM.

MM is found in periodic table if you don't know it yet.

So we get : n(Mg) = 25.5 g ÷ 24.305 g/mol. = 1.0491... mol.

Step 2: Look at the stoichiometric ratios in the formula. Mg : O = 2:1.

Therefore, the moles of oxygen is half the number of moles of Magnesium.

n(O2) = 0.5 x 1.0491... mol = 0.52458... mol

Step 3: Now convert moles of Oxygen to grams using m = n x MM. Hey presto you have your answer!

m(O2) = 0.52458... x 2(15.999) = 16.7856... grams.

To 3 significant figures this is 16.8grams.

Let me know if you are confused about anything.

User Abdelhakim AKODADI
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.