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Twice the difference of a number n and seven is equal to four less than the product of five and the number n. What is that value of n?

N=-10/3n= -1n= 1n= 10/7

User CFUser
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1 Answer

6 votes

Answer:

n=-10/3

Explanation:

"Twice the difference of a number n and seven is equal to four less than the product of five and the number n" translates into 2(n-7) = 5n - 4. To solve, isolate the variable n.

2(n-7) = 5n - 4

2n - 14 = 5n - 4

2n - 10 = 5n

-10 = 3n

-10/3 = n

User Brian Fitzpatrick
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