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Which complex number has a distance of |17| from the origin on the complex plane?

1 Answer

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Hello from MrBillDoesMath!

Answer:

z = 17 e^(i t)

where "t" is a real number

Discussion:

distance (17 e^(it)) = => using deMoivre's formula)

distance ( 17 ) distance ( cost + i sintt) ) =

17 sqrt( (cost)^2 + (sint)^2) = => (cost)^2 + (sint)^2 =1

17 * 1

= 17

Thank you,

MrB

User Brett Duncavage
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