Answer:
The value of expression 2(3x^3 + 2y^2) when x = -2 and y = 12 is 528
Explanation:
To find the value of 2(3x^3 + 2y^2)
The expression is 2(3x^3+2y^2)
x = -2 and y = 12
Substitute the value of x and y in the above expression we get,
2[3(-2)^3 +2(12)^2] = 2[ (3 * (-8) ) + (2*144)]
= 2[-24 + 288] = 2 * 264 = 528
Therefore the value of expression 2(3x^3 + 2y^2) when x = -2 and y = 12 is 528